The Cart and the Bumper — Impulse Is the Area

Mecânica Intermédio Grátis VR · AR
The Cart and the Bumper — Impulse Is the Area – Mecânica
The Cart and the Bumper — Impulse Is the Area – Mecânica

A launcher pushes a dynamics cart along a level track into a spring bumper mounted on a force sensor, while a motion sensor at the other end records the cart's velocity. The cart bounces back and coasts away; press play to run the experiment once, and drag the timeline to any moment of it. Four sliders set the cart's mass m, the launch speed vi, the bumper's stiffness k and its restitution e; they start at 0.50 kg, +0.60 m/s, 600 N/m and 0.80. The velocity and force graphs share one time axis and are drawn up to the moment shown, and every setting you try is logged in a table: vi and vf read from the flat parts of the velocity graph, the contact time Δt, Δp = m(vf − vi) and the area J under the force pulse.

Como usar esta simulação

O que observar

A física por trás

Take the direction towards the bumper as positive. The bumper gives back the fraction e of the speed — it unloads along a steeper line than it loads — so the cart leaves at vf = −e·vi. At the starting values vf = −0.8 × 0.60 = −0.48 m/s and Δp = m(vf − vi) = 0.50 × (−0.48 − 0.60) = −0.54 N s. The force sensor is read 1000 times a second, and the area under its pulse, the impulse J = ∫F dt, comes out at −0.54 N s as well: negative, because the bumper pushes the cart back towards the motion sensor. The stiffness changes only the shape of the pulse. The contact lasts (π/2)(1 + e)√(m/k) and the force peaks at vi√(mk): 0.082 s and 10.4 N at 600 N/m, 0.20 s and 4.2 N at 100 N/m. Longer contact, smaller force, the same area — J = FΔt = Δp. A heavier cart or a faster launch changes Δp, and the area follows it exactly; a bouncier bumper (larger e) changes the momentum more, because Δp = −m·vi(1 + e).

impulseimpulse–momentum theoremarea under a force–time graphcoefficient of restitutiondynamics cartforce sensormotion sensor3D